Question

In triangle ABC, D and E are points on sides AB and AC respectively such that DE is parallel to BC and AD:DB=3:1. If EA =2.2cm, then find AC

Answer 1

Step-by-step explanation:

Answer:

AC=8.8 cm

Explanation:

In ΔABC, D and E are the points on sides AB and AC respectively such that DE parallel to BC as shown in attach figure.

AD:DB=3:1 or \frac{AD}{DB}=\frac{3}{1}DBAD=13

If EA=6.6 cm

Using Basic proportionality theorem, In a triangle a line is drawn parallel to one side of a triangle and intersect the other two side at distinct points, the other two sides are divided in the same ratio.

\therefore \frac{AD}{DB}=\frac{AE}{EC}∴DBAD=ECAE

Substitute the value of AD:DB and AE. We get

\frac{3}{1}=\frac{6.6}{EC}13=EC6.6

EC=2.2 cm

We need to find length of AC.

AC=AE+EC

AC=6.6+2.2

AC=8.8 cm

Answer 2

Answer:

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