Question

In triangle abc d and e are points on the sides ab and ac de is parallel to bc if bd= x-3 ab=2x ce= x-2 ac = 2x+3 find x

Answer 1

Answer:

DE ll BC

angle D = angle B

angle A = angle A

= ∆ABC ~ ∆ADE (AA similarity)

== AD/AB = AE/ AC

= AB-BD / AB = AC-EC/ AC

= 2x-(x-3) / 2x = 2x+3-(x-2)

= 2x-x+3/2x = 2x+3-x+2/2x+3

= x+3/ 2x = x+5/ 2x+3

= 2x2 + 6x +3x +9 = 2x2 +10x

= 9x +9 = 10x

= x =9

Step-by-step explanation:

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