In triangle ABC D and E are the points on the sides AB and AC respectively such that DE parallel to BC AD/DB is 3/4 and AC is 15cm Find AE
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4
Answer:
15/7*3
45/7
6.42
6.4 cm
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13
AE = 6.43 cm
Let AE be x and EC be 15-x
According to the Basic Proportional Theorem,
AD/DB = AE/EC
3/4 = x/(15-x)
By cross multiplying,
4x = 3(15-x)
4x = 45-3x
7x = 45
x = 45/7
x = 6.43 cm
Therefore, AE = 6.43 cm
Hope this helps!
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