In triangle ABC,DandE are the points on AB and Ac respectively such that DE parallel to BC.If AD=2.4cm,AE=3.2cm,DE=2cm,and BC=5cm then find BD and CE
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AD/BD = AE/CE = DE/BC..... (COMPONENDO OF BPT)
AD/BD = DE/BC
2.4/BD = 2/5
2.4×5 = 2BD
12.0/2 = BD
BD = 6CM
AE/CE = DE/BC
3.2/CE = 2/5
3.2×5 = 2CE
16.0/2 = CE
CE = 8CM
AD/BD = DE/BC
2.4/BD = 2/5
2.4×5 = 2BD
12.0/2 = BD
BD = 6CM
AE/CE = DE/BC
3.2/CE = 2/5
3.2×5 = 2CE
16.0/2 = CE
CE = 8CM
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