Question

in triangle abc,DE||AB.if ad=2x,dc=x+3,be=2X-1 & ce=x then find the value of x

Answer 1

I hope you will get satisfied with my solution.

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Answer 2

AD = 2x ,DC = x + 3, BE =2x - 1 ,CE = x

Using Thales Theorem

$\bf\huge\frac{CD}{AD} = \frac{CE}{BE}$

$\bf\huge\frac{x+3}{2x} = \frac{x}{2x-1}$

5x = 3

$x=\bf\huge\frac{3}{5}$