Math, asked by karthik8279, 11 months ago

In
triangle
ABC, DE // BC and AD: DB= 3:5
AE :EC is equal to​

Answers

Answered by vanshikatripathi2007
1

Step-by-step explanation:

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points than the other two sides are divided in the same ratio.

SOLUTION:

In ∆ABC , DE||BC

AD/DB= AE/EC

[ By basic PROPORTIONALITY theorem]

AD/DB= AE/(AC-AE)

3/5 = AE / (4.8 - AE)

3(4.8 - AE) = 5 AE

14.4 - 3AE = 5AE

14.4 = 5AE+3AE

14.4 = 8AE

AE = 14.4/8

AE= 1.8

Hence, AE is = 1.8 cm

HOPE THIS WILL HELP YOU

Answered by kanthachbh
0

The answer for yr question is

1.5:2.5 ratio

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