In triangle ABC, DE||BC. If AD= 2cm, DB=3cm and AE=3.7cm, find AC
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Answered by
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by BPT
AD/DB=AE/EC
2/3=3.7/EC
EC=111/20
EC=5.5
SO,
AC=AE+EC
AC=3.7+5.5
AC=9.2
AD/DB=AE/EC
2/3=3.7/EC
EC=111/20
EC=5.5
SO,
AC=AE+EC
AC=3.7+5.5
AC=9.2
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