In triangle ABC ,DE is parallel to BC and DE =4cm ,BC =8cm ,area of triangle ADE =25 sq .cm ,find the area oftriangle ABC
Pranavraja3:
Using BPT Take the squares of sides in ratio.
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20
Its answer is 100 cm square
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51
ar of ADE=1/2×4×h=25
h=25/2
ADE is similar to ABC
ratio of sides=ratio of heights
4:8=25/2:x
x=25
h of ABC=25
ar of ABC =1/2×25×8
=100
h=25/2
ADE is similar to ABC
ratio of sides=ratio of heights
4:8=25/2:x
x=25
h of ABC=25
ar of ABC =1/2×25×8
=100
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