Question

In triangle abc de is parallel to bc if ad =4cm and bd=8cn find ratio of ae:ce

Answer 1

Answer:

ae:ce = 1:2

Step-by-step explanation:

Now in a ABC, dellbc

by BPT theorem,

ad/bd = ae/ce

4/8 = 4/8 ===> 1/2=1/2

Therefore, ae:ce= 1:2