Question

in triangle ABC DE is parallel to BC if AE:EC=4:13 and AB=20.4cm then find AD

Answer 1

Answer:

in tri ABC

since DE//BC,

(AD/DB)=(AE/EC)

(AD/DB)=(AE)/(AC-AE)

(4/13)=(AE)/(20.4-AE)

4(20.4-AE)=13AE

81.6-4AE=13AE

17AE=81.6

AE=81.6/17

AE=4.8