In triangle ABC, DE parallel BC intersecting AB and AC at D and E.if AD= 9cm DB=12cm AE=6cm Find EC
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By Basic Proportionality Theorem,
AD/DB = AE/EC
9/12 = 6/EC
EC = 6×12/9
= 72/9
EC = 8 cm
AD/DB = AE/EC
9/12 = 6/EC
EC = 6×12/9
= 72/9
EC = 8 cm
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