In triangle ABC , DE parallel to BC and AD: DB = 2:3 . Determine area triangle (ADE) : Area triangle (ABC) .
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Hey friend,
Here is your answer,
______________________________________________________________
DE║BC
AD : DB = 2 : 3
AD = 2
DB 3
DB + 1 = 3 + 1
AD 2
DB+AD = 3+2
AD 3
AB = 5
AD 3
ar(ΔADE) = AD² = 5² = 25
ar(ΔABC) AB² 3² 9
______________________________________________________________
Hope this helped you !!
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Here is your answer,
______________________________________________________________
DE║BC
AD : DB = 2 : 3
AD = 2
DB 3
DB + 1 = 3 + 1
AD 2
DB+AD = 3+2
AD 3
AB = 5
AD 3
ar(ΔADE) = AD² = 5² = 25
ar(ΔABC) AB² 3² 9
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
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