Question

in triangle abc DE parallel to BC and AD/DB=2/5 if EC is equal to 4.8 cm find the height of AE​

Answer 1

Step-by-step explanation:

AD/DB= AE/EC

2/5=AE/4.8

cross multiplication

AE5= 4.8/2 = 2.4

AE = 2.4 - 5

AE = - 2.6

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