In triangle ABC , E is the mid point of side AB and D is a point on AC such that DE || BC . which of the following is true- AE|| AC , AE= AC , AE=½AC , AE =DE
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Answer:
Step-by-step explanation:
given:-
AD is the median of ΔABC and E is the midpoint of AD
Through D draw DG∣∣BF
In ΔADG
E is the midpoint of AD and EF∣∣DG
By converse of midpoint theorem we have
F is midpoint of AG and AF=FG ..............1
Similarly, in ΔBCF
D is the midpoint of BC and DG∣∣BF
G is midpoint of CF and FG=GC ..............2
From equations 1 and 2
we will get
AF=FG=GC........3
AF+FG+GC=AC
AF+AF+AF=AC ......... from eq 3
AF=AC
AF=(1/3)AC
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