Question

In triangle ABC , E is the midpoint of median ad such that BE produced meets AC at F. If AC = 10.5 , then find AF In cm.

Answer 1

Thank you for asking this question. Here is your answer:

The diagonals DP & AC bisect each other at O

O is the midpoint of AC as well as DP (this is an equation 1)

ADCP is a parallelogram, AP = DC and AP parallel DC, but D is mid point of BC (this is given)

AP = BD and AP parallel BD

BDPA is also a parallelogram

diagonals AD & BP bisect each other at E

BEP is a single straight line intersecting AC at F

In triangle ADP, E is the mid point of AD and  O is the midpoint of PD

property of centroid of triangles, it lies at 2/3 of the median from vertex.  

AF = (2/3)AO  (this is equation 2)

From equation 1 and 2 we can get this:

AF = (2/3)*(1/2)*(AC)

= (1/3)(AC)

= 10,5/3

= 3.5 cm

If there is any confusion please leave a comment below.

Answer 2

Hello mate, Wassup

Here is your solution...................