Question

In triangle ABC ,External isoscelesof angle A and angle C intersect at the point O. If angle A=60 degree ,then angle BOC=?​

Answer 1

The angle BOC is 120°

Step-by-step explanation:

ABC is a triangle in which A=60°, bisectors of angles B and C meet at point O.

In triangle ABC

60°+B+C=180°. or. B+C=120°…………….(1)

B0 is bisector of. angle B and CO is bisector of angle C . Thus

angle OBC=B/2. , angle. OCB = C/2.

In triangle OBC

angle BOC+ angle OBC. + angle OCB. =180°

angle BOC. +B/2 +C/2=180°

angle BOC = 180°- 1/2(B+C). Putting B+C=120° from eqn.(1)

angle BOC. = 180°-1/2(120°) = 180°-60°. = 120°.

Answer 2

Answer:

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