In triangle ABC, if 3 angle =4 angle =6 angle, then =?
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Hi ,
Let 3A = 4B = 6C = k ( k is a constant )
A = k/3 ; B = k/4 ; C = k/6
In ∆ABC ,
A + B + C = 180°
k/3 + k/4 + k/6 = 180
multiply each term with 12 , we get
4k + 3k + 2k = 180 × 12
=> 9k = 180 × 12
k = ( 180 × 12 )/9
k = 240
Therefore ,
A = k/3 = 240/3 = 80°,
B = k/4 = 240/4 = 60°,
C = k/6 = 240/6 = 40°
I hope this helps you.
: )
Let 3A = 4B = 6C = k ( k is a constant )
A = k/3 ; B = k/4 ; C = k/6
In ∆ABC ,
A + B + C = 180°
k/3 + k/4 + k/6 = 180
multiply each term with 12 , we get
4k + 3k + 2k = 180 × 12
=> 9k = 180 × 12
k = ( 180 × 12 )/9
k = 240
Therefore ,
A = k/3 = 240/3 = 80°,
B = k/4 = 240/4 = 60°,
C = k/6 = 240/6 = 40°
I hope this helps you.
: )
Answered by
1
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