Question

what is the sum of first 49 natural number?

Answer 1

Sum = n * (First + Last) / 2
Sum = 49 * (1 + 49) / 2
Sum = 49 * 50 / 2
Sum = 2450 / 2
Sum = 1225 

Answer 2

Concept: Natural numbers square measure a region of the amount system which incorporates all the positive integers from one until eternity and also are used for investigating purpose. It doesn't embody zero (0).

Sum of n natural numbers will be outlined as a type of progression wherever the add of n terms as organized during a sequence with the primary term is being one, n is being the quantity of terms in conjunction with the ordinal term.

Find: Calculate the sum of first 49 natural numbers.

Solution:

The first natural number is 1.

Therefore, a=1.

The common difference is 1.

Therefore, d=1.

Total number is 49.

Therefore, n=49.

Sum of 49 natural number = n[2a+(n-1)d]/2

                                            = 49[2×1+(49-1)×1]/2

                                            = 49[2+48]/2

                                            = 49×50/2

                                            = 49×25

                                            = 1,225.

Final answer: Sum of first 49 natural number is 1,225.

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