In Triangle ABC , If AB is the greatest side , then ptrove that angle C > 60 deg
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Answered by
71
in a triangle abc
AB>AC and AB>BC
according to inequality theorem angles opposite to equal sides are equal and angle opposite to longest side will be largest and vice versa
hence angle C>angle B and angle C>angle A
since in a triangle sum of all angles=180degree
therefore largest angle will be more than 60degree
example=let angle B=angle A = 59 degree
so angle C=180-(59+59)
angle C=180-118
angle C=62degree
HENCE PROVED
I hope that you must have understood it
AB>AC and AB>BC
according to inequality theorem angles opposite to equal sides are equal and angle opposite to longest side will be largest and vice versa
hence angle C>angle B and angle C>angle A
since in a triangle sum of all angles=180degree
therefore largest angle will be more than 60degree
example=let angle B=angle A = 59 degree
so angle C=180-(59+59)
angle C=180-118
angle C=62degree
HENCE PROVED
I hope that you must have understood it
Answered by
40
Given: ∆ABC in which AB is the greatest side.
To prove:Angle C > 60°
Proof: In ∆ABC
AB>AC
Angle C > Angle A...(i)
AB>BC
Angle C > Angle A...(ii)
Adding (i) and (ii)
2C> A+B
3C>A+B+C
3C>180°
Angle C> 60° [Hence Proved]
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