In triangle ABC if AD is the median then show that AB2 + AC2 = 2(AD2 + BD2)
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In triangle ABC, AD is median
then , BD = BC
in triangles ABD and ADC
AB^2 = AD^2 + BD^2 .........(1)
AC^2 = AD^2 + BC^2 ............(2)
now add both the equations,
AB^2 + AC^2 = AD^2 + AD^2 + BD^2+ BC^2
AB^2 + AC^2 = 2AD^2 + 2BD^2 [ since BD = BC]
AB^2 + AC^2 = 2[AD^2 + BD^2]
hence proved...
niteshyadav30:
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hope this helps. i have no idea why it keeps appearing upside down
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