In triangle ABC if angle A =45 angle C = 60, then find the shortest side of the triangle?
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total angle ABC=180
then angle A=45
angle C=60
hence a+b+c=180
;45+b+60=180
105+b=180
b=180 - 105=75; hence shortest side of the triangle ABC . B=75
then angle A=45
angle C=60
hence a+b+c=180
;45+b+60=180
105+b=180
b=180 - 105=75; hence shortest side of the triangle ABC . B=75
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