In triangle abc if angle a+angle b=125 degrees and angle a+angle c=113 degrees find a
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Answered by
59
a+b=125
a+c=113
a+b+c=180
a+b=180-c
180-c= 125
c=55
a+55=113
a=58
a+c=113
a+b+c=180
a+b=180-c
180-c= 125
c=55
a+55=113
a=58
Answered by
20
a+b=125
a+c=113
a+b+c=180
a+b=180-c
180-c= 125
c=55
a+55=113
a=58
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