Question

in triangle ABC,if angle A = angle B =2 angle C, find each of the angels​

Answer 1

Answer:

Let be angle A = x

then

angle B = x and angle C = 2x .

Now according to Sum property of ∆ ,

x + x + 2x = 180

4x = 180

x = 45°.

Hence,

A = 45°

B = 45°

C = 90°.

Hope, you understand well.

Answer 2

Answer:

angle A=72°

angle B=72°

angle C=36°

Step-by-step explanation:

Given: angleA=angleB=2angleC

angleA=angleB----(1)

angleA=2angleC => angleC=angleA/2----(2)

In a triangle, angleA+angleB+angleC=180°

angleA+angleA+angleA/2=180° (from (1)&(2))

5angleA/2=180°

angleA=(180×2)/5

angleA=72°

angleB=angleA=72°

angleC=angleA/2=72/2=36°