Math, asked by bhandaripriya312, 5 months ago

In triangle ABC if angle B=09°,ten sine A cos A =_​

Answers

Answered by Anonymous
13

Answer:

ANSWER

Given in △ ABC, ∠B=90o.

This given A+C=180o−90o=90o......(1).

Now,

sinA.cosC+cosA.sinC

=sin(A+C)

=sin(90o)

=1.

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