Question

in triangle ABC if DE||BC and AD= 2x AE=2x-1 DB= x+3 CE=x then find the value of x​

Answer 1

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AD = 2x ,DC = x + 3, BE =2x - 1 ,CE = x

Using Thales Theorem

\bf\huge\frac{CD}{AD} = \frac{CE}{BE}

\bf\huge\frac{x+3}{2x} = \frac{x}{2x-1}

5x = 3

x=\bf\huge\frac{3}{5}