in triangle ABC if DE||BC BPT
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Answered by
20
From the question it is given that,
DE∥BC and BD=CE
So, we have to prove that ABC is an isosceles triangle.
Consider the triangle ABC,
AD/DB=AE/EC
Given, DB=EC … [equation (i)]
Then, AD=AE … [equation (ii)]
By adding equation (i) and equation (ii) we get,
AD+DB=AE+EC
So, AB=AC
Therefore, △ABC is an isosceles triangle.
Answered by
1
Answer:
----------AD/DB=AE/CE
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