Question

in triangle ABC if DE parallel to BC,prove that AB/AD=AC/AE​

Answer 1

Answer:

Step-by-step explanation:

As DE//BC

<ADE=<ABC and <AED=<ACB

 so triangles ABC and ADE are simillar

therfore AD/AB=AE/AC

Answer 2

given = DE || BC

to prove : AB/AD = AC/AE

proof : AD/DB = AE/EC ( from BPT)

DB/AD+1=EC/AE+1

= DB +AD /AD = EC+AE/AE

= AB/AD = AC / AE

Hence proved

hope it helps

#Ravalika Rajula

: )