Question

The sum of the 4 and 8 terms of an Ap in 24 and the sum of the 6+10 terms is 44 find the first three terms of an Ap

Answer 1

Step-by-step explanation:

4th term = a + 3d

8th term = a + 7d

4th + 8th = 24

a + 3d + a + 7d = 24

2a + 10d = 24

2( a+ 5d) = 24

a + 5d = 24/2

a + 5d = 12 equ (1)

6th term = a + 5d

10th term = a + 9d

6th + 10th = 44

a + 5d + a + 9d = 44

2a + 14d = 44

2(a + 7d) = 44

a + 7d = 44/2

a + 7d = 22 equ (2)

subtract (2) - (1)

2d = 10

d = 10/2

d = 5

substitute d = 5 in equ (1)

a + 5d = 12

a + 5(5) = 12

a + 25 = 12

a = 12 - 25

a = -13

the AP is

-13, -8, - 3, 2, 7, 12,

hope you get your answer