The sum of the 4 and 8 terms of an Ap in 24 and the sum of the 6+10 terms is 44 find the first three terms of an Ap
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Step-by-step explanation:
4th term = a + 3d
8th term = a + 7d
4th + 8th = 24
a + 3d + a + 7d = 24
2a + 10d = 24
2( a+ 5d) = 24
a + 5d = 24/2
a + 5d = 12 equ (1)
6th term = a + 5d
10th term = a + 9d
6th + 10th = 44
a + 5d + a + 9d = 44
2a + 14d = 44
2(a + 7d) = 44
a + 7d = 44/2
a + 7d = 22 equ (2)
subtract (2) - (1)
2d = 10
d = 10/2
d = 5
substitute d = 5 in equ (1)
a + 5d = 12
a + 5(5) = 12
a + 25 = 12
a = 12 - 25
a = -13
the AP is
-13, -8, - 3, 2, 7, 12,
hope you get your answer
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