Question

in triangle ABC,if <A:<B:<C = 1/2:1/3:1/6,then calculate the measures of <A,<B,<C​

Answer 1

The angle sum property of a triangle says that sum of all sides of a triangle is equal to 180°.

So, let <A = 1/2x ,<B= 1/3x ,<C= 1/6x ( taking x as constant)

now <A+<B+<C = 180°

so 1/2x + 1/3x + 1/6x = 180°

=》 3x + 2x + 1x / 6 =180° ( Taking 6 as LCM)

=》 6x/6 = 180°

=》 x= 180 °

Now,

<A = 1/2 × 180 = 90 °

<B = 1/3 × 180 = 60 °

<C= 1/6 × 180 = 30 °

So angles are 90 ° 60 ° 30° respectively.