Question

in triangle ABC,if tanA=1/2 tanB=1/3, then measure angle c​

Answer 1

Answer:

135 °

Step-by-step explanation:

tan C = tan(180- (A+B))= - tan (A+B)

=$-\frac{tan A +tan B}{1 - tanAtanB}$

= $-\frac{\frac{1}{2} + \frac{1}{3} }{1 - \frac{1}{2} \frac{1}{3} }$

= $-\frac{5/6 }{1 - 1/6 }$

=$-\frac{\frac{5}{6}}{ \frac{5}{6} }$

= -1

C= (180 - 45 )degree

  =  135 degree