Question

In triangle ABC is an isosceles such that AB= AC,then prove that altitude ADfrom A on BC bisect BC .

Answer 1

Answer:

Step-by-step explanation:

Take the triangles ABD and ADC prove them congruent and BD= CD by cpct which implies AD bisects BC

take angle B=C AD=AD common and AB=AC which is given hope this will help°!!

Answer 2

Answer:

Step-by-step explanation:

Given : AB = AC, AD⊥BC [∠ABD = ∠ADC = 90°]

To Prove: AD bisects BC ( BD = CD)

Proof:

In ΔABD and ΔACD

∠ADB = ∠ADC          [ 90° Each]

    AB = AC               [ Given]

    AD = AD              [ Common ]

∴ΔABD ≅ ΔACD     [ By RHS]

∴ BD = CD               [ C. P. C. T.]

Hence, we can say that AD is bisecting BC