Question

In triangle ABC is right angled at c.then find values of cos (a+b) and sin(a+b)

Answer 1

cos (a+b)=0
sin(a +b) =1
because in a right triangle the sum of the two acute angles is equal to 90°

Answer 2

Answer:

cos(A+B) = 0

sin(A+B) = 1

Explanation:

Here ΔABC is a right-angled triangle, where angle "C" is right-angled. We know that the sum of three angles in a triangle is always 180º. Here C is 90º, so (A+B) = (180º-90º) = 90º.

We know that,

cos90º = 0 therefore cos(A+B) = 0

sin90º = 1. therefore sin(A+B) = 1

Hope for choosing my answer as the "Brainliest"!