In triangle ABC.l,right angled, at B, BD perpendicular AC .If AB =5.7cm, BD=3.8cm and CD=5.4cm,find BC....if we solve by pythagoras we get Value of BC as 6.3 and if we solve by right angle property of Similarity of triangle we get BC as 8.1 cm...why does answer vary and which one is the correct and reason why
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easy ha bap sa puch la kuta
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Step-by-step explanation:
By Pythagoras theorem
Hyp^2=opp^2+adj^2
BC^2=3.8^2+5.4^2
BC^2=14.44+29.16
BC^2=43.6
BC=√43.6=2√10.9
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