Math, asked by binit1838, 11 months ago

In triangle ABC, LM parallel to BC and AL/LB=2/3 ,AM=5cm ,find AC

Answers

Answered by gurjan12singh12
20



BY BPT

AL/LB=AM/MC

2/3=5/MC

CROSS MULTIPLE

2MC=15

MC=15/2

AC= AM+MC

=5+15/2

=(10+15)/2

= 25/2

=12.5

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