In triangle ABC, LM parallel to BC and AL/LB=2/3 ,AM=5cm ,find AC
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BY BPT
AL/LB=AM/MC
2/3=5/MC
CROSS MULTIPLE
2MC=15
MC=15/2
AC= AM+MC
=5+15/2
=(10+15)/2
= 25/2
=12.5
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