in triangle abc <b=90°, ab= 3cm, cosA=3/5 what is the length of ac?
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Answer:
Answer
sinC=
AC
AB
=
6
3
=
2
1
C=sin
−1
[
2
1
]=30
∘
∠B+∠C+∠A=180
∘
90
∘
+30+∠A=180
∘
∠A+=60
∘
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