Question

In triangle abc o is the midpoint of bc. Prove ab2+bc2= 2(bo2+oc2)

Answer 1

Step-by-step explanation:

if o is the mid point it will form two triangles of 90°at o point

by theorem we get

oa^2+ob^2=ab^2 (1)

&

oa^2+oc^2=ac^2 (2)

by adding (1)&(2) we get

oa^2+ob^2+oa^2+oc^2=ab^2+ac^2

2oa^2+ob^2+oc^2=ab^2+ac^2

ob=oc so

2 (ob^2+oc^2)=ab^2+bc^2