In triangle ABC,PQ||BC,AP=2,PB=6,AQ=3,QC=9.Prove thatBC=4PQ
yajat1810:
sorry bro
your question is wrong
it is that what i proved in the solution
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draw a diagram like this
here AP = 2cm
PB = 6cm
AP/PB = 2/6 = 1/3
AQ = 3cm
QC = 9cm
AQ/QC = 3/9 = 1/3
AP/PB = AQ/QC
So, here ∆APQ is similar to ∆ABC
so, PQ/BC = 1/3
PQ×3 = BC
here AP = 2cm
PB = 6cm
AP/PB = 2/6 = 1/3
AQ = 3cm
QC = 9cm
AQ/QC = 3/9 = 1/3
AP/PB = AQ/QC
So, here ∆APQ is similar to ∆ABC
so, PQ/BC = 1/3
PQ×3 = BC
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Read question again? figure is right
yes
but i said of question
We want to prove BC=4PQ
this question is wrong
what i sais is this mate
said*
It's impossible
I think Basic proportionality Theorem is useful here
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