in triangle ABC , PQ is parallel to BC , if AB = 4AP and AQ = 4 then AC = how much
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Given : PQ is parallel to BC , if AB = 4AP and AQ = 4
To Find : AC
Solution:
PQ || BC
ΔABC and ΔAPQ
∠A = ∠A common
∠B = ∠P ( corresponding angles)
∠C = ∠Q ( corresponding angles)
=> ΔABC ≈ ΔAPQ
=> AB/AP = AC/ AQ
=> 4AP/AP = AC/4
=> 4 = AC/4
=> AC = 4 x 4
=> AC = 16
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Answered by
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Angle C = Angle Q (corresponding)
∆ABC is corrsesponding to ∆APQ
AB/AP = AC/AQ
4AP/AP = AC/4
4=AC/4
AC = 4×4
AC = 16
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