in triangle ABC pqr all altitude are equal
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Answered by
0
Answer:
answer
Explanation:
all are equally
Answered by
0
Answer:
To prove
ΔABC∼ΔPQR{
PQ
AB
=
QR
BC
=
PR
AC
→(i)
InΔABMandΔPQN
∠ABM=∠PQN{ΔABC∼ΔPQR}
∠BMA=∠QNP{each90
∘
}
ByAA,
ΔABM∼ΔPQN
ByC.P.S.T
=
PQ
AB
=
QN
BM
=
PN
AM
→(ii)
ΔAXCandΔPYR
∠C=∠R{given}
PR
AC
=
QR
BC
{Given}
PR
AC
=
2
1
QR
2
1
BC
PR
AC
=
YR
XC
BYSAS,
ΔAXC∼ΔPYR
PY
AX
=
PR
AC
{ByC.P.S.T}
From(1),(2)and(3)
PN
AM
=
PY
AK
Explanation:
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