in triangle ABC, prove that (AB+BC +CA) is greater than 2AB
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Answer: since the sum of two sides in a triangle is greater than the third one. which is the required result.
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Hola Mate !!
Here's your answer :-
since the sum of two sides in a triangle is greater than the third one.
BC + CA > AB
adding AB on the both sides of the inequality:
we get ,
AB + BC + CA > AB + AB
=> AB + BC + CA > 2AB
which is the required result.
hope this helps you.
cheers!!
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