Math, asked by hetvivadalia8827, 1 year ago

In triangle ABC, r1cotA/2 + r2 cotB/2 + r3cotC/2=

Answers

Answered by sprao534

7

=s tanA/2 cotA/2+stanB/2.CotB/2+s TanC/2CotC/2=3s=3(a+b+c)/2

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