Question

In triangle ABC ray BD bisects angel ABC. A-D-C, side DE parallel to side BC, A-E-B then prove that, AB/BC=AE/EB

Answer 1

Answer:

In triangle ABC,

BD bisects angle ABC-given. (A-D-C)

DE parallel to side BC-given. (A-E-B)

therefore,

by midpoint theorem,

AB/BC=AE/EB.

-hence proved

Answer 2

Answer:

bro you use wrong theorem