Question

IN triangle ABC right angld at B,AB=5,A C=10FIND ANGLE C

Answer 1

Answer:

30 degrees

Step-by-step explanation:

Given that

AB=5 and AC=10

In triangle ABC

SinC=AB/AC

SinC=5/10

SinC=1/2

SinC=sin 30

C=30 degrees

Answer 2

Answer:

Angel C=45°

Step-by-step explanation:

In triangle ,sum of all angel=180°

let the angle be X

Angel,A+B+C=180°

Angel B=90°(Given)

X+90°+X=180°

2X+90°=180°

2X=180°-90°

2X=90°

X=90°/2

X=45°

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