Math, asked by kaushalkrsingh, 9 months ago

in triangle ABC right angle at B angle A=angle B ,find the value of sin A× sin B+cos A × cos B

Answers

Answered by ksonakshi70

0

Answer:

clearly

angle A =angle B

hence

sinA sinB + cos A cosB

= sinAsinA + cos Acos A

= sin^2A +cos^2A

= 1

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