in triangle ABC right angle at B , tanA= 1/root3 find cosAcosB-sinAsinC guys it's so urgent
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Answer:
sinA.cosC + cosA.sinC = 1
cosA.cosC - sinA.sinC = 0
Step-by-step explanation:
Formula used:
sin(A+B) = sinA.cosB + cosA.sinB
cos(A+B)= cosA. cosB - sinA.sinB
Given:
tanA=1/√3
A=30°
since B is right angle, C=60°
Now,
sinA.cosC + cosA.sinC
=sin(A+C)
=sin(30°+60°)
=sin90°
=1
cosA.cosC - sinA.sinC
=cos(A+C)
=cos(30°+60°)
=cos90°
=0
Step-by-step explanation:
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