in triangle ABC right-angled at B,AB=24 cm, BC=7cm. determine : 1 sin A,cos A 2 sin c,cos c
Answers
Answered by
3
(by pythahorus theorem, hypotenuse = root (base^2 + altitude^2)
AC= root ( 24^2 + 7^2) = root (576 +49) = root (625) = 25 cm
Sin A = BC/AC = 7/25
Cos A = AB/AC = 24/25
Sin C = AB/AC = 24/25
Cos C = BC/AC = 7/25
THANK YOU :)
AC= root ( 24^2 + 7^2) = root (576 +49) = root (625) = 25 cm
Sin A = BC/AC = 7/25
Cos A = AB/AC = 24/25
Sin C = AB/AC = 24/25
Cos C = BC/AC = 7/25
THANK YOU :)
Similar questions