Question

In triangle ABC right angled at B,AB=24cm and BC=7cm . Determine​

Answer 1

Answer:-

$\large\sf{By,using\:Pythagoras\:theorem}$

$\small\sf{{AC}^{2}=√{AB}^{2}+{BC}^{2}}$

$\longrightarrow$$\small\sf{√{(24)}^{2}+{(7)}^{2}}$

$\longrightarrow$$\small\sf{√(576+49)}$

$\longrightarrow$$\small\sf{√625}$

$\longrightarrow$$\small\sf{25cm}$

1) $\small\sf{SinA=\frac{BC}{AC}=\frac{7}{25}}$

$\small\sf{CosA=\frac{AB}{AC}=\frac{24}{25}}$

2) $\small\sf{SinC=\frac{AB}{AC}=\frac{24}{25}}$

$\small\sf{CosC=\frac{BC}{AC}=\frac{7}{25}}$