in triangle abc right angled at B ab is equal to 24 cm BC is equal to 7 cm determine Sin A cos a sin C Kosi
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Answer:
in right angle triangle abc B=90 BC=7cm ab =24cm
by PGT
(h)^=(p)^+(b)^
(h)^= (24) ^+(7)^
(h)^= 576+49
(h)^= 625
h=25
now,
sinC=p\h=24/25
cosC=b/h=7/25
then again,
by PGT
h^=p^+b^
h^=(7)^+(24)^
h^=49+ 576
h^=625
h= 25
now ,
sinA=p/h=7/25
cosC=b/h=24/25
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