Question

In triangle ABC, right angled at B, AC=13cm, AB=12cm, then tanA-cotC is equal to i)-1 iv)1/2 ii)1 iii)0​

Answer 1

Answer:

0

Step-by-step explanation:

by Pythagoras

AC^2 = AB^2 + BC^2

so(13)^2= (12)^2+(BC)^2

now BC=5

Now tanA=5/12

cotC=5/12

so tanA-cotC=5/12-5/12=0