in triangle abc right angled at B and BD perpendicular to AC if ad is equal to 8 cm and CD is equal to 10 cm then ab is equal to
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Given :
- ∠ABC = 90°
- AD = 8
- CD = 10
To find :
- Length of AB
Solution :
- Refer the attached figure.
- BD is perpendicular to AC.
∴ ∠ADB = ∠CDB = 90°
- Here, we use the Pythagoras theorem which states that in a right angled triangle, the square of the hypotenuse is equal to the sum of squares of other two sides.
∴ AB² = AD² + BD²
∴ AB² = 8² + BD² ....(1)
- Applying Pythagoras theorem in ΔCDB,
BC² = CD² + BD²
∴ BC² = 10² + BD² ....(2)
- Applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
18² = (8² + BD²) + (10² + BD²) ....(from (1) and (2))
∴ 324 = 164 + 2 BD²
∴ 2 BD² = 160
∴ BD² = 80 ....(3)
- Substituting (3) in equation (1),
AB² = 64 + 80
∴ AB² = 144
∴ AB = 12 units
Answer : The length of AB is 12 units.
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hope this helps...thank you
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